Seja $L=\displaystyle\underset{x\rightarrow +\infty}{\lim}(\textrm{log}(x))^{\frac{1}{x}}$

\begin{enumerate}pyB
subst = ["$L=1$.","$L=+\infty$.","$L=0$.","$L=e$."]
unsorted = shuffle( subst )
certa[0] = unsorted[0]
opts = unsorted[1]
for i in opts:
    emit( "\n\\item ", i)
pyE
\end{enumerate}