Seja $f(x)=\displaystyle\frac{(\textrm{sen}^{2}(2x)+2)^{2}}{5}$
\begin{enumerate}pyB
subst = [r"$f'(x)=\displaystyle\frac{8(\textrm{sen}^{2}(2x)+2)\textrm{sen}(2x)\textrm{cos}(2x)}{5}$.",r"$f'(x)=\displaystyle\frac{8(\textrm{sen}^{2}(2x)+2)\textrm{sen}(2x)\textrm{cos}(2x)}{25}$.",r"$f'(x)=\displaystyle\frac{8(\textrm{sen}^{2}(2x)+2)\textrm{sen}(2x)}{5}$.",r"$f'(x)=\displaystyle\frac{2(\textrm{sen}^{2}(2x)+2)\textrm{cos}(2x)}{25}$."]
unsorted = shuffle( subst )
certa[0] = unsorted[0]
opts = unsorted[1]
for i in opts:
    emit( "\n\\item ", i)
pyE
\end{enumerate}